540A - Combination Lock - CodeForces Solution


implementation *800

Please click on ads to support us..

Python Code:

n = int(input())
k1 = list(map(int, input()))
k2 = list(map(int, input()))
print(sum(min(10 - abs(k1[i] - k2[i]),
 abs(k1[i] - k2[i])) for i in range(n)))

C++ Code:

#include <bits/stdc++.h>
#include <string>
using namespace std; 

int main(){
    int n; 
    string s1, s2; 
    cin>>n>>s1>>s2; 
    int answer = 0; 
    for(int i=0; i<n; i++){
        int i1 = (int)s1[i] - 48, i2 = (int)s2[i] - 48;
        answer += min(abs(i1 - i2), abs(max(i1, i2) - 10) + min(i1, i2)); 
    }
    cout<<answer<<endl; 
}


Comments

Submit
0 Comments
More Questions

2148. Count Elements With Strictly Smaller and Greater Elements
2149. Rearrange Array Elements by Sign
2150. Find All Lonely Numbers in the Array
2151. Maximum Good People Based on Statements
2144. Minimum Cost of Buying Candies With Discount
Non empty subsets
1630A - And Matching
1630B - Range and Partition
1630C - Paint the Middle
1630D - Flipping Range
1328A - Divisibility Problem
339A - Helpful Maths
4A - Watermelon
476A - Dreamoon and Stairs
1409A - Yet Another Two Integers Problem
977A - Wrong Subtraction
263A - Beautiful Matrix
180C - Letter
151A - Soft Drinking
1352A - Sum of Round Numbers
281A - Word Capitalization
1646A - Square Counting
266A - Stones on the Table
61A - Ultra-Fast Mathematician
148A - Insomnia cure
1650A - Deletions of Two Adjacent Letters
1512A - Spy Detected
282A - Bit++
69A - Young Physicist
1651A - Playoff